Solving Quadratic Equations by Factoring: A Comprehensive Guide
Unlock the power of factoring to solve quadratic equations. Our step-by-step approach covers essential techniques, common pitfalls, and real-world applications to boost your algebra skills.

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Now Playing:Solve quadratic equations by factoring – Example 0a
Intros
  1. Solve by factoring a trinomial: 2x212x+10=02x^2-12x+10=0
  2. Solve by factoring a difference of squares: 25x249=025x^2-49=0
Examples
  1. Solve by Factoring a Trinomial
    Solve each equation by factoring.
    1. 3x2+x10=03x^2+x-10=0

    2. 7x2+35=42x7x^2+35=-42x

Solving quadratic equations by factoring
Notes
Review the chapter on "Factoring" to refresh your memory if you don't quite remember how to factor polynomials. It will definitely help you solve the questions in this lesson!
Difference of Squares: a2b2=(a+b)(ab)a^2-b^2=(a+b)(a-b)
Concept

Introduction to Solving Quadratic Equations by Factoring

Welcome to our lesson on solving quadratic equations by factoring! This fundamental skill is crucial in algebra and beyond. To kick things off, we've prepared an introduction video that will give you a clear overview of the process. This video is essential viewing, as it lays the groundwork for understanding the topic. Before we dive in, it's important to ensure you're comfortable with factoring. If you need a refresher, I highly recommend reviewing the 'Factoring chapter' first. Don't worry if it seems challenging at first with practice, you'll become proficient. Remember, factoring is like a puzzle, and solving quadratic equations is simply putting those puzzle pieces together. As we progress, we'll explore various techniques and real-world applications of quadratic equations. Stay engaged, ask questions, and most importantly, enjoy the learning process! Let's embark on this mathematical journey together.

Example

Solve by Factoring a Trinomial
Solve each equation by factoring.
3x2+x10=03x^2 + x - 10 = 0

Step 1: Write the Equation in Standard Form

The given equation is already in the standard form of a quadratic equation, which is ax2+bx+c=0ax^2 + bx + c = 0. Here, a=3a = 3, b=1b = 1, and c=10c = -10.

Step 2: Identify the Coefficients

Identify the coefficients aa, bb, and cc from the equation 3x2+x10=03x^2 + x - 10 = 0. Here, a=3a = 3, b=1b = 1, and c=10c = -10.

Step 3: Factor the Quadratic Expression

To factor the quadratic expression, we need to find two numbers that multiply to ac=3(10)=30a \cdot c = 3 \cdot (-10) = -30 and add up to b=1b = 1. We need to find pairs of factors of -30 that add up to 1.

Possible pairs are:

  • (1, -30)
  • (-1, 30)
  • (2, -15)
  • (-2, 15)
  • (3, -10)
  • (-3, 10)
  • (5, -6)
  • (-5, 6)

Among these pairs, the pair that adds up to 1 is (-5, 6).

Step 4: Rewrite the Middle Term

Rewrite the middle term xx using the pair found in the previous step. The equation becomes:

3x25x+6x10=03x^2 - 5x + 6x - 10 = 0

Step 5: Factor by Grouping

Group the terms to factor by grouping:

(3x25x)+(6x10)=0(3x^2 - 5x) + (6x - 10) = 0

Factor out the greatest common factor (GCF) from each group:

x(3x5)+2(3x5)=0x(3x - 5) + 2(3x - 5) = 0

Factor out the common binomial factor:

(3x5)(x+2)=0(3x - 5)(x + 2) = 0

Step 6: Solve for x

Set each factor equal to zero and solve for xx:

3x5=03x - 5 = 0

3x=53x = 5

x=53x = \frac{5}{3}

And

x+2=0x + 2 = 0

x=2x = -2

Step 7: Verify the Solutions

Substitute x=53x = \frac{5}{3} and x=2x = -2 back into the original equation to verify the solutions.

For x=53x = \frac{5}{3}:

3(53)2+(53)10=03\left(\frac{5}{3}\right)^2 + \left(\frac{5}{3}\right) - 10 = 0

3259+5310=03 \cdot \frac{25}{9} + \frac{5}{3} - 10 = 0

759+159909=0\frac{75}{9} + \frac{15}{9} - \frac{90}{9} = 0

75+15909=0\frac{75 + 15 - 90}{9} = 0

09=0\frac{0}{9} = 0

For x=2x = -2:

3(2)2+(2)10=03(-2)^2 + (-2) - 10 = 0

34210=03 \cdot 4 - 2 - 10 = 0

12210=012 - 2 - 10 = 0

0=00 = 0

Both solutions satisfy the original equation.

FAQs

Here are some frequently asked questions about solving quadratic equations by factoring:

1. How do I solve a quadratic equation by factoring?

To solve a quadratic equation by factoring, follow these steps: 1. Ensure the equation is in standard form (ax² + bx + c = 0). 2. Factor the left side of the equation. 3. Set each factor equal to zero. 4. Solve the resulting linear equations to find the roots.

2. What is the formula for factoring?

There isn't a single formula for factoring, but common methods include: - Factoring out the greatest common factor (GCF) - Using the difference of squares formula: a² - b² = (a+b)(a-b) - For trinomials (ax² + bx + c), find two numbers that multiply to ac and add to b

3. How do you solve quadratic equations step by step?

1. Write the equation in standard form (ax² + bx + c = 0). 2. Factor the quadratic expression. 3. Apply the zero product property: set each factor to zero. 4. Solve the resulting linear equations. 5. Check your solutions by substituting them back into the original equation.

4. What is the formula for solving a quadratic equation?

While factoring doesn't use a specific formula, the quadratic formula can solve any quadratic equation: x = (-b ± (b² - 4ac)) / (2a) where ax² + bx + c = 0 is the standard form of the quadratic equation.

5. What are some common mistakes when solving quadratic equations by factoring?

Common mistakes include: - Forgetting to set each factor to zero - Incorrectly identifying factors - Not considering the coefficient of x² when it's not 1 - Failing to check solutions in the original equation - Overlooking the possibility of repeated roots

Prerequisites

Understanding the foundation of algebra is crucial when tackling more advanced concepts like solving quadratic equations by factoring. One of the key prerequisites is solving polynomial equations, which forms the basis for working with quadratic expressions. This skill allows students to manipulate and simplify complex algebraic expressions, setting the stage for more advanced problem-solving techniques.

Before diving into quadratic equations, it's essential to master factoring by taking out the greatest common factor. This fundamental skill is the cornerstone of solving quadratic equations by factoring, as it helps identify common terms that can be factored out, simplifying the equation and making it easier to solve.

Another important prerequisite is understanding perfect square trinomials. Recognizing these special forms can significantly speed up the factoring process and provide insights into the nature of the quadratic equation's roots. Similarly, familiarity with the difference of squares is crucial, as many quadratic equations can be simplified using this factoring technique.

While focusing on factoring, it's also beneficial to explore alternative methods like using the quadratic formula and completing the square. These approaches provide a well-rounded understanding of quadratic equations and offer solutions when factoring is not possible or practical.

Understanding the nature of roots of quadratic equations through the discriminant is also vital. This knowledge helps predict the types of solutions a quadratic equation might have before solving it, guiding the choice of solving method.

For a more comprehensive grasp, students should familiarize themselves with the quadratic function in general form. This understanding provides a visual representation of quadratic equations and their solutions, enhancing overall comprehension of the topic.

Lastly, exploring the applications of quadratic equations in real-world scenarios helps students appreciate the practical importance of mastering these solving techniques. This connection to real-life problems motivates learning and reinforces the relevance of quadratic equations in various fields.

By building a strong foundation in these prerequisite topics, students will find solving quadratic equations by factoring more accessible and intuitive. Each concept contributes to a deeper understanding of quadratic equations, preparing students for more advanced mathematical challenges and applications in their academic and professional futures.