Static equilibrium problems

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Now Playing:Static equilibrium problems – Example 1a
Examples
  1. Cable and beam in static equilibrium
    1. A 20.0 kg lamp is hung from a uniform 12.5 kg beam as shown. Find the tension in the wire, and the horizontal and vertical forces acting on the hinge. PHYS 8 3 1a

    2. A 25.0 kg lamp is hung from an 18.0 kg uniform beam as shown. The total length of the beam is 8.50 m. Find the tension in the wire, and the horizontal and vertical forces acting on the hinge. PHYS 8 3 1b

Translational equilibrium
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Notes

In this lesson, we will learn:

  • Solving statics problems using both translational and rotational equilibrium

Notes:

  • An object or group of objects that are not moving are in static equilibrium.
  • In static equilibrium, the conditions for both translational and rotational equilibrium must be met.
Conditions for Translational Equilibrium

ΣF=0N\Sigma F = 0 N

or equivalently:

ΣFx=0N\Sigma F_{x} = 0 N and ΣFy=0N\Sigma F_{y} = 0 N

ΣF:\Sigma F: sum of all forces, in newtons (N)

ΣFx:\Sigma F_{x}: sum of all force components in x direction, in newtons (N)

ΣFy:\Sigma F_{y}: sum of all force components in y direction, in newtons (N)


Torque

τ=Fd\tau = F_{\perp}d

τ\tau: torque, in newton meters (N·m)

F:F_{\perp}: component of force perpendicular to dd, in newtons (N)

d:d: distance from point of rotation, in meters (m)


Conditions for Rotational Equilibrium

Στ=0\Sigma \tau = 0 N·m

or simpler equation:

total CWCW τ\tau = total CCWCCW τ\tau

Στ:\Sigma \tau : sum of all torques, in newton meters (N·m)

total CWCW τ\tau: magnitude of all torques in the clockwise direction, in newton meters (N·m)

total CCWCCW τ\tau: magnitude of all torques in the counterclockwise direction, in newton meters (N·m)