Mastering 3-Dimensional Planes: From Equations to Applications
Dive into the world of 3D planes, mastering vector and general equations. Develop crucial spatial reasoning skills for advanced mathematics and real-world problem-solving in engineering and physics.

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  2. Examples0/5 watched
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Now Playing:3 dimensional planes – Example 0a
Intros
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  1. 3-Dimensional Planes Overview:
  2. 3-Dimensional Planes Overview:
    Equation of a Plane
    • How do we get the formula for the equation?
    • a(xx0)+b(yy0)+c(zz0)=0a(x-x_0) + b(y-y_0) + c(z-z_0) = 0
    • What we need for the formula
  3. 3-Dimensional Planes Overview:
    Finding a Plane with a Parallel Plane & 1 point
    • Get the Normal Vector
    • Plug into the formula
Examples
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  1. Finding the Equation of a Plane
    Find the equation of the plane which contains the points (1,3,0)(1, 3, 0), (2,7,6)(-2, 7, 6) and (1,0,1)(1, 0, 1).
    3-D coordinate system
    Notes
    Notes:

    Equation of a Plane
    Couple sections ago, we saw that the equation of plane can be expressed as ax+by+cz=dax+by+cz=d. However, this equation does not give much information. So suppose we have the following graph:
    plane graph
    Where r\vec{r} and r0\vec{r_0} are position vectors for points PP and P0P_0 respectively, and n\vec{n} is a normal vector that is orthogonal (perpendicular) to the plane.
    Since rr0\vec{r} - \vec{r_0} is on the plane, then n\vec{n} is orthogonal to rr0\vec{r} - \vec{r_0}. In other words, their dot products should give 0.
    So,

    (rr0)n=0(<x,y,z><x0,y0,z0>)<a,b,c>=0(\vec{r} - \vec{r_0}) \cdot \vec{n} = 0 \to (\lt x,y,z\gt - \lt x_0,y_0, z_0\gt) \cdot \lt a,b,c\gt = 0
    <xx0,yy0,zz0><a,b,c>=0\to \lt x-x_0 , y-y_0, z-z_0\gt \cdot \lt a,b,c\gt = 0
    a(xx0)+b(yy0)+c(zz0)=0\to a(x-x_0) + b(y-y_0) + c(z-z_0) = 0

    Which is formula for the equation of a plane.

    The key to finding the equation of a plane is finding two things:
    1. The normal vector (orthogonal to the plane)
    2. A point on the plane.
    Then you can just plug those into the formula to get the equation!
    Concept

    Introduction to 3-Dimensional Planes

    3-dimensional planes are fundamental geometric concepts that extend our understanding of space beyond lines and points. Building upon our knowledge of 3-dimensional lines, these planes represent flat surfaces that stretch infinitely in all directions within a 3D coordinate system. The introduction video accompanying this topic serves as a crucial visual aid, helping students grasp the abstract nature of these mathematical constructs. It demonstrates how planes intersect with axes and other planes, forming complex spatial relationships. Understanding 3-dimensional planes is essential for various fields, including architecture, engineering, and computer graphics. The video illustrates key concepts such as normal vectors, plane equations, and how multiple planes can define 3D shapes. By mastering 3-dimensional planes, students gain a powerful tool for analyzing and describing spatial relationships in the world around them, paving the way for advanced topics in geometry and calculus.

    Example

    Equation of a Plane

    • How do we get the formula for the equation?
    • a(xx0)+b(yy0)+c(zz0)=0a(x-x_0) + b(y-y_0) + c(z-z_0) = 0
    • What we need for the formula

    Step 1: Understanding the Concept of a Plane

    A plane in three-dimensional space can be visualized as an infinitely large, flat sheet of paper. It extends infinitely in all directions within its two-dimensional surface. To understand the equation of a plane, we first need to grasp this concept. A plane is defined by a point on the plane and a normal vector that is perpendicular to the plane.

    Step 2: The Standard Equation of a Plane

    The standard form of the equation of a plane is given by Ax+By+Cz=DAx + By + Cz = D. However, this form does not provide much information about the plane itself, such as how to draw it or what vectors are involved. Therefore, we need a more informative way to express the equation of a plane.

    Step 3: Points and Vectors on the Plane

    Consider two points on the plane: P0P_0 and PP. Let P0P_0 be a specific point on the plane with coordinates (x0,y0,z0)(x_0, y_0, z_0), and let PP be any point on the plane with coordinates (x,y,z)(x, y, z). We can create vectors from these points: R0R_0 associated with P0P_0 and RR associated with PP. These vectors are R0=(x0,y0,z0)R_0 = (x_0, y_0, z_0) and R=(x,y,z)R = (x, y, z).

    Step 4: The Normal Vector

    The normal vector NN is a vector that is perpendicular to the plane. This vector is crucial because it helps define the orientation of the plane. If NN is perpendicular to the plane, then any vector on the plane will be orthogonal to NN.

    Step 5: Creating a Vector on the Plane

    To find a vector on the plane, we can subtract R0R_0 from RR, resulting in the vector RR0R - R_0. This vector lies on the plane. Since NN is perpendicular to the plane, it is also perpendicular to RR0R - R_0.

    Step 6: Dot Product and Perpendicular Vectors

    If two vectors are perpendicular, their dot product is zero. Therefore, the dot product of NN and RR0R - R_0 must be zero. Mathematically, this is expressed as (RR0)N=0(R - R_0) \cdot N = 0.

    Step 7: Expanding the Dot Product

    Expanding the dot product, we get: (xx0,yy0,zz0)(a,b,c)=0 (x - x_0, y - y_0, z - z_0) \cdot (a, b, c) = 0 This simplifies to: a(xx0)+b(yy0)+c(zz0)=0 a(x - x_0) + b(y - y_0) + c(z - z_0) = 0 This is the equation of the plane in a more informative form.

    Step 8: Understanding the Equation

    The equation a(xx0)+b(yy0)+c(zz0)=0a(x - x_0) + b(y - y_0) + c(z - z_0) = 0 provides more information than the standard form. It tells us the normal vector (a,b,c)(a, b, c) and a specific point (x0,y0,z0)(x_0, y_0, z_0) on the plane. This makes it easier to understand and visualize the plane.

    Step 9: Using the Equation to Find Planes

    When solving problems involving planes, look for two key pieces of information: the normal vector and a point on the plane. Once you have these, you can plug them into the equation a(xx0)+b(yy0)+c(zz0)=0a(x - x_0) + b(y - y_0) + c(z - z_0) = 0 to find the equation of the plane.

    FAQs
    1. What is the difference between a 3D plane and a 2D plane?

      A 3D plane extends infinitely in three-dimensional space, while a 2D plane is confined to two dimensions. In 3D space, a plane has a normal vector perpendicular to its surface, which is not present in 2D planes. 3D planes are described by equations involving x, y, and z coordinates, whereas 2D planes use only x and y.

    2. How do you find the normal vector of a plane?

      The normal vector of a plane can be found by taking the cross product of two non-parallel vectors lying on the plane. Alternatively, if the plane equation is given in the form Ax + By + Cz + D = 0, the normal vector is <A, B, C>.

    3. What is the significance of the D term in the general equation of a plane?

      In the general equation of a plane Ax + By + Cz + D = 0, the D term represents the plane's distance from the origin multiplied by the magnitude of the normal vector. It determines the plane's position in 3D space relative to the origin.

    4. How can you determine if two planes are parallel?

      Two planes are parallel if their normal vectors are scalar multiples of each other. In other words, if the planes have equations Ax + By + Cz + D = 0 and Ax + By + Cz + D = 0, they are parallel if A/A = B/B = C/C.

    5. What is the relationship between a plane's normal vector and its equation?

      The normal vector of a plane is directly related to the coefficients of x, y, and z in the plane's equation. For a plane Ax + By + Cz + D = 0, the normal vector is <A, B, C>. This relationship allows for easy conversion between vector and general forms of plane equations.

    Prerequisites

    When delving into the world of 3-dimensional planes, it's crucial to have a solid foundation in certain mathematical concepts. Two key prerequisite topics that play a significant role in comprehending 3-dimensional planes are Conics - Circle and Graphing from slope-intercept form y=mx+b.

    Understanding Conics - Circle is essential when working with 3-dimensional planes, particularly when dealing with the vector equation of a plane. Circles, as a type of conic section, provide a foundation for grasping the concept of curved surfaces in three-dimensional space. The principles learned in studying circles can be extended to comprehend how planes intersect with spheres or other curved surfaces in 3D.

    Moreover, the knowledge of Graphing from slope-intercept form y=mx+b is invaluable when working with the general form of a plane equation. This prerequisite topic helps students understand how to represent linear relationships graphically, which is a crucial skill when visualizing and analyzing planes in three dimensions. The slope-intercept form serves as a stepping stone to more complex equations used in 3D geometry.

    By mastering these prerequisite topics, students can more easily grasp the concepts of 3-dimensional planes. The Conics - Circle topic provides insights into curved surfaces and their interactions with planes, while Graphing from slope-intercept form builds the foundation for understanding linear relationships in higher dimensions.

    When studying 3-dimensional planes, students will encounter various equations and representations. The vector equation of a plane, which is related to the concepts learned in Conics - Circle, describes the plane using a point and a normal vector. This representation is particularly useful when working with intersections and angles between planes.

    On the other hand, the general form of a plane equation, which builds upon the principles of Graphing from slope-intercept form, allows for a more algebraic approach to describing planes. This form is essential for solving systems of equations involving multiple planes and determining their intersections.

    By thoroughly understanding these prerequisite topics, students can develop a strong intuition for 3-dimensional geometry. The skills acquired from studying Conics - Circle and Graphing from slope-intercept form serve as building blocks for more advanced concepts in 3D space, such as finding distances between points and planes, determining angles between planes, and analyzing the intersections of multiple planes.

    In conclusion, a solid grasp of these prerequisite topics is crucial for success in understanding and working with 3-dimensional planes. By investing time in mastering Conics - Circle and Graphing from slope-intercept form, students will be well-prepared to tackle the challenges and complexities of 3D geometry with confidence and competence.