Surface area of 3-dimensional shapes

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Now Playing:Surface area of 3 d shapes– Example 1
Examples

  1. Surface area of 3-dimensional shapes
    1. What are the dimensions of the cutout piece?

    2. How does the surface area of the original rectangular object change after cutting out the corner piece?

Introduction to surface area of 3-dimensional shapes
Notes
In this section, we will learn how to calculate the surface area of 3D objects. We will also look further into the subject ? What would happen to the surface area if the shapes are cut into pieces? How about a piece is cut out of the shape?

Surface area of 3D shapes

Prior to this, you've probably learned how to find the surface area of 2D shapes—for example, the area of a square or a rectangle. But how about 3D shapes? You can find the surface area for them too! Finding the area of 3D shapes just means finding the sum of all the areas of the outside surfaces on a shape.

What is a prism?

In geometry, a prism is a polyhedron. This means that is has two faces that are the same called the bases of the prism. Other faces of the prism are all parallelograms. Oftentimes, when you're finding the surface area of a 3D shape, you'll be working with a prism such as a 3D triangle.

What is a rectangular prism

Amongst the prisms, the most popular one people usually start with are rectangular prisms. A rectangular prism has rectangles as its two bases. It's a 3D rectangle. To find the surface area of it, you simply find the areas of the six rectangles that make up its shape.

Example problems

We'll guide you through a few questions dealing with the surface area of a prism. As we mentioned before, most starter problems take you through questions that deal with a rectangular prism first, and that's what we'll be doing here.

Question 1

Surface area of 3-dimensional shapes
Surface area of 3-dimensional shapes

a) What are the dimensions of the cutout piece?

Solution:

From the question's diagrams, we can determine the measurements of the cutout piece. You can find the below numbers by finding the side of the rectangle and then subtracting the parts that aren't part of the cutout piece. For example, the length of one of the rectangle's side is 27cm. The side right beside the cutout piece is 15cm. Subtracting 15 from 27 gives us 12, and therefore, the cutout piece has a length of 12.

Look for the side length of the cutout piece.
Side length of the cutout piece

Here are the measurements for the cutout piece if we isolated it.

Measurements of the cutout piece from the diagram above.
Measurements of the cutout piece

b) How does the surface area of the original rectangular object change after cutting out the corner piece?

Solution:

Surface area is not equalled to the volume. If you were to look at this shape from top, left, or right, you'll still see the whole rectangle. The surface area actually didn't change.

Therefore, there is no change.

Question 2:

Below is a rectangular object formed by six blocks which all have the same size.

Surface area of 3-dimensional shapes
Surface area of 3-dimensional shapes

a) What are the dimensions of one block?

Solution:

Since the six blocks are equal, the dimensions of one block can be found by dividing up the measurements into appropriate amounts to allocate its portion to the respective block. The 6cm actually remains the same since the height of 1 block versus the whole rectangular object is the same.

The 30cm has to be divided into 2, giving us 15 cm. The 18cm will have to be divided into 3 sections, which is 6cm each. Therefore our final dimensions is:

Dimensions of small blocks that make up the big block in the diagram provided above
Dimensions of small blocks

b) What is the surface area of the rectangular object?

Solution:

Area=Base×Height=Length×WidthArea = Base \times Height = Length \times Width

Find the area of the sides of the small blocks in the above diagram
Find the area of different sides of the small block

Side A: (15 ×\times 6) ×\times 2 = 180

Side B: (6 ×\times 6) ×\times 2 = 72

Side C: (15 ×\times 6) ×\times 2 = 180

180 + 72 + 180 = 432 cm2cm^{2}

c) Calculate the ratio of the surface area of the rectangular object to the total surface area of the six blocks.

Solution:

We have the surface area of one block. We now need to look the surface area of the whole object.

Look for the total surface area of the whole block.
Total surface area of the whole block

Side A: (30 ×\times 6) ×\times 2 = 360

Side B: (18 ×\times 6) ×\times 2 = 216

Side C: (30 ×\times 18) ×\times 2 = 1080

360 + 216 + 1080 = 1656 cm2cm^{2}

Then the ratio is equalled to: 4321656\frac{432}{1656}, which when simplified equals 623\frac{6}{23}.

Feel free to play around with this interactive geometry shape that can show you how the surface area of 3D objects are calculated.

To further your understanding of the surface area of a 3D object, take a look at the surface area and volume of prisms lesson, or the ones on pyramids, cylinders, cones, or spheres.